integral 1-x^2/1-x dx

Integral
∫ (1 - x²)/ (1 - x)  dx =
=  ∫ (1 - x)(1 + x) / (1 -x) dx
= ∫ 1 + x  dx
= x + 1/2 x² + c
= 1/2 x ( x + 2) +c