Tentukan nilai integral berikut! integral (10x pangkat 4 + 6x pangkat 3 + 2) dx

(10x⁴ + 6x³ + 2) dx
= (10 / 4+1)x^(5+1) + (6 / 3+1)x^(3+1) + 2x + C
= 2x^5 + 6/4 x⁴ + 2x + C
= 2x^5 + (3/2)x⁴ + 2x + C
^ tanda pangkat

Materi : Integral
Bahasan : Integral Aljabar Tak Tentu
Jawaban : [tex]2x^5 + \frac{3}{2}x^{4} + 2x + C [/tex]

Langkah - langkah :
[tex] \int\limits {(10x^4+6x^3+2)} \, dx \\ \\ = \frac{10x^{4 + 1}}{4 + 1} + \frac{6x^{3+1}}{3+1} + \frac{2x^{0+1}}{0+1} +C \\ \\ = \frac{10x^{5}}{5} + \frac{6x^{4}}{4} + 2x +C \\ \\ = 2x^5 + \frac{3}{2}x^{4} + 2x + C [/tex]