integral x+2/√x²+4x dx.

Penyelesaian:

∫ [tex] \frac{x+2}{ \sqrt{x^2 + 4x} } dx[/tex]
= ∫ (x+2)(x² + 4x)^-1/2 dx

d(x² + 4x) = (2x + 4) dx
d(x² + 4x)/(2x + 4) = dx

= ∫ (x+2)(x² + 4x)^-1/2 d(x² + 4x)/(2x + 4)
= 1/2 ∫ (x² + 4x)^-1/2 d(x² + 4x)
= 1/2 . 2 (x² + 4x)^1/2 + c
= [tex] \sqrt{x^2 + 4x} + c[/tex]