F'(×)=-×2+2×-3 dan f(3)=0

Penyelesaian:

f'(x) = -x² + 2x - 3

f(x) = ∫-x² + 2x - 3 dx
f(x)= -1/3.x³ + x² -3x + c
f(3) = -1/3.(3)³ + (3)² - 3(3) = 0
= -9 + 9 - 9 + c =0
c = 9

f(x) = 1/3.x³ + 2x - 3x + 9