jika a＝-2,b＝4,dan c＝-6,maka hitunglah nilai dari a.2a-3b+4c b.ab+bc-ac c.(2a+3b-c)-(a-2b+3c)

a. 2a-3b+4c = 2 x (-2) -3 x 4 + 4 x (-6) = -4-12-24 = -40
b. ab+bc-ac = -2 x 4 + 4 x (-6) - (-2) x(-6) = -8-24-12 = -44
c. (2a+3b-c) - (a-2b+3c) = (2 x (-2) + 3x4 - (-6)) - ((-2)-2x4+3x(-6))
=-4+12+6- (-2-8-18)
=-4+12+6+2+8+18
=42

a.) 2a-3b+4c
=(2×-2)-(3×4)+(4×(-6))
=(-4)-12+(-24)
=-16+(-24)
=-40.
b.)2b+bc-ac
=(2×4)+(4×(-6))-(-2×(-6))
=8+(-24)-12
=-16-12
=-28.
c.)(2a+3b-c)-(a-2b+3c)
={(2×-2)+(3×4)-(-6)}-{-2-(2×4)+(3×(-6))}
={-4+12-(-6)}-{-2-8+(-18)}
=14-(-28)
=42.

maaf kalau salah.