integral cos 5x Sin X DX, tolong di bantu dengan caranya. terima kasih

Integral Fungsi Trigonometri.

cos α sin β = 1/2 [sin (α + β) - sin (α - β)]
∫ sin x dx = -cos x + C

∫ cos 5x sin x dx
= ∫ 1/2 [sin (5x + x) - sin (5x - x)] dx
= 1/2 ∫ (sin 6x - sin 4x) dx
= 1/2 (-1/6 cos 6x + 1/4 cos 4x) + C
= -1/12 cos 6x + 1/8 cos 4x + C
= 1/8 cos 4x - 1/12 cos 6x + C