Matematika

Pertanyaan

diketahui ³log5 = p dan ³log2 = q . nilai 20log 200  =

2 Jawaban

  • ³log 200 / ³log 20 = ³log 2³ . ³log 5² / ³log 5 . ³log 2²
                             = 3 ³log2 + 2 ³log5 / ³log5 + 2 ³log2
                             = 3q + 2p / p + 2q
  • 20log [tex] ^{20} log 200 = \frac{log 200}{log 20} \\ = \frac{log2.100}{log 4.5} \\ = \frac{log 2 + log 10^{2} }{log 2^{2} + log 5} \\ = \frac{log 2 + 2}{2 . log2 + log5} \\ = \frac{ ^{3}log2 + 2}{2 . ^{3}log 2 + ^{3} log 5} \\ = \frac{q+2}{2q+p} [/tex]

Pertanyaan Lainnya