Matematika

Pertanyaan

tolong dijawab no. 2 dan no.3
tolong dijawab no. 2 dan no.3

1 Jawaban

  • 3. a) y³ * 2y7 * (3y)²
    = y³ * 2y7 * 3² y²
    = y¹² * 18
    = 18 y¹²

    Maaf yg tadi salah ✌

    b) b * 2y7 * b³ * y ²
    = 2 b⁴ y9
    c) 3m³ x (MN) ⁴
    = 3 m³ * m⁴ * n⁴
    = 3 m7 * n4
    d) (tn³)⁴ * 4 t³
    = t1 * n12 * 4t3
    =4 n12 t7

    e) (2x³) * 3 (x²y²)³ * 5 y⁴
    = 2x3 * 3x6y6 * 5 y4
    = 2 x9 * 3y10 * 5
    = 30 * x9 * y10