hasil dari (2+3)³-³√2.197 + 4³= n nilai n yg tepat adalh...? tulung yh kak...

(2+3)^3 - ^3V2197 + 4^3
= 5^3 - (2197)^1/3 + 4^3
= 5^3 - (13^3)^1/3 + 4^3
= 5^3 - 13^3/3 + 4^3
= 5^3 - 13^1 + 4^3
= 125 - 13 + 64
= 176

atau
(2+5)^3 - ^3V2197 + 4^3
= 7^3 - (2197)^1/3 + 4^3
= 7^3 - (13^3)^1/3 + 4^3
= 7^3 - 13^3/3 + 4^3
= 7^3 - 13^1 + 4^3
= 343 - 13 + 64
= 394