Matematika

Pertanyaan

a. (ײ+4×-1) -(2ײ+4×)
b. 2(×+2y-×y) +5(2×-3y+5×y)
c. (5a-6+ab) -(a+2ab-1)

1 Jawaban

  • A. (ײ+4×-1) -(2ײ+4×)
        = x² + 4x - 1 - 2x² - 4x
        = -x² - 1

    B.
    2(×+2y-×y) +5(2×-3y+5×y)
        = 2x + 4y - 2xy + 10x - 15y + 25xy
        = 2x + 10x + 4y - 15y - 2xy + 25xy
        = 12x - 11y + 23xy

    C.
    (5a-6+ab) -(a+2ab-1)
        = 5a - 6 + ab - a - 2ab + 1
        = 5a - a + ab - 2ab - 6 + 1
        = 4a - ab - 5

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